Question

Urine has a $pH$ of $6.0$. If a patient eliminates $1300mL$ of urine per day, how many gram equivalents of the acid he eliminates per day?

• A. $1.3\times {10}^{-4}$
• B. $1.3\times {10}^{-6}$
• C. $2.4\times {10}^{-4}$
• D. $2.4\times {10}^{-6}$

Answer 1

Answer: (B)

$1.3\times {10}^{-6}$

$pH=6$

$\left[H^{+}\right]=1\times {10}^{-6}$ $N$

$\left[H^{+}\right]=\frac{Givenweight}{Gramequivalentweight}\times \frac{1000}{VolumeinmL}$

$\left[H^{+}\right]=No.ofgramequivalent\times \frac{1000}{VolumeinmL}$

${10}^{-6}=No.quadofGramequivalents\times \frac{1000}{1300}$

No. of grams Equivalents $=1.3\times {10}^{-6}$