Question

Urine has a $pH$ of $6$.If a patient eliminates $1.3$ litres of urine per day how many moles of $H^{+}$ ions does he urinate?

• A. $1.3$ x ${10}^{-3}$
• B. $1.3$ x ${10}^{-6}$
• C. $1.3$ x ${10}^{-7}$
• D. $1.3$ x ${10}^6$

Answer 1

The correct option is B $1.3$ x ${10}^{-6}$

$pH=6$

$\left[H^{+}\right]={10}^{-6}moles/L$

hence, moles of $H^{+}$ in $1$ L urine $=1.3\times {10}^{-6}$