Question

Urine normally has a $pH$ of $6.0$. A patient eliminates $1.3$ litres of urine per day. How many moles of $H^{+}$ ions does he eliminate in a day?

• A. $1.3\times {10}^{-3}$
• B. $1.3\times {10}^{-6}$
• C. $1.94N$
• D. $1.94\times {10}^{-2}N$

Answer 1

The correct option is A $1.3\times {10}^{-3}$

Given,

$pH$ of Urine$=6.0$

$\Rightarrow \left[H^{+}\right]$ i.e. concentration of $H^{+}={10}^{-6}$ $mol{L}^{-1}$

$\Rightarrow$ For $1L$ of urine ${10}^{-6}$ moles of $H^{+}$ ions are present

$\therefore$ If $1.3L$ of urine is eliminated, then the moles of $H^{+}$ ion eliminated will be

$1L⟶{10}^{-6}$

$1.3L⟶x$

$x=1.3\times {10}^{-6}$

$\therefore 1.3\times {10}^{-6}$ moles of $H^{+}$ ions are eliminated if $1.3L$ of urine is eliminated per day.