wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Use a suitable identity to get each of the following products:
(x2+3y4)(x2+3y4)

A
x24+316xy+34y2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x24+32xy+916y2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x24+34xy+916y2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
x22+32xy+98y2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C x24+34xy+916y2
(x2+3y4)(x2+3y4)=(x2+3y4)2
=(x2)2+2×x2×3y4+(3y4)2[Using Identity(a+b)2=a2+2ab+b2]
=x24+34xy+916y2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon