Use a suitable identity to get following products.
$(2 y + 5) (2 y + 5)$

4 y^{2} + 20 y + 25

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4 y^{2} + 10 y + 25

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4 y^{2} + 20 y + 15

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4 y^{2} + 20 y - 25

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Solution

The correct option is A $4 y^{2} + 20 y + 25$
$(2 y + 5) (2 y + 5)$
Using,
$(a + b)^{2} = a^{2} + 2. a . b + b^{2}$ we get the above equation.
$= (2 y + 5)^{2}$
$= (2 y)^{2} + 2.2 y .5 + 5^{2}$
$= 4 y^{2} + 20 y + 25$

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Similar questions

Using an identity expand :
$(2 y + 5) (2 y + 5)$

(2 y + 5) (2 y + 5)

Evaluate: (2y+5)(2y+5).

Factorise:
$4 y^{2} + 20 y + 25$

20 (y + 4) (y^{2} + 5 y + 3) \div 5 (y + 4)

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