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Factorisation by Regrouping Terms

Use direct me...

Question

Use direct method to evaluate :
$(2 + a) (2 - a)$

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Solution

$(2 + a) (2 - a) = (2)^{2} - (a^{2}) = 4 - a^{2}$ $[∵ (a + b) (a - b) = a^{2} - b^{2}]$

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Similar questions

Use direct method to evaluate :

(i) (x + 1)(x - 1)

(ii) (2 + a)(2 - a)

(iii) (3b - 1)(3b + 1)

(iv) ( 4 + 5x)(4 - 5x)

(v) (2a + 3)(2a - 3)

(vi) (xy + 4)(xy - 4)

(vii) (ab + x^2)(ab - x^2)

(viii) (3x^2 + 5y^2)(3x^2 - 5y^2)

(vi) (xy + 4)(xy - 4)

(ix) $(z - \frac{2}{3}) (z + \frac{2}{3})$

(x) $(\frac{3}{5} a + \frac{1}{2}) (\frac{3}{5} a - \frac{1}{2})$

(xi) (0.5 - 2a)(0.5 + 2a)

(xii) $(\frac{a}{2} - \frac{b}{2}) (\frac{a}{2} + \frac{b}{3})$

(a b^{2} + 4 c) (a b^{2} - 4 c)

a^{2} b^{4} - 16 c^{2}

1

0

(a + b) (a - b) = a^{2} - b^{2}

103 \times 97

(a + b) (a - b) = a^{2} - b^{2}

7.7 \times 8.3

(a + b) (a - b) = a^{2} - b^{2}

9.8 \times 10.2

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