Question

Use direct method to evaluate the following product:
$(a{b}^2+4c)(a{b}^2-4c)$, then the answer is $a^2{b}^4-16c^2$
If true the enter $1$ and if false then enter $0$

Answer 1

Multiplying by using direct method, we get
$(a{b}^2+4c)(a{b}^2-4c)$
$=a{b}^2(a{b}^2-4c)+4c(a{b}^2-4c)$
$=a^2{b}^4-16c^2+4a{b}^{2}c-4a{b}^{2}c$
$=a^2{b}^4-16c^2$