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Gibb's Energy and Nernst Equation

Use E∘ valu...

Question

Use $E^{\circ}$ values to calculate $△ G^{\circ}$ for the reaction
$F e^{2 +} + A g^{+} \to F e^{3 +} + A g$
$E_{A g^{+} / A g}^{\circ} = 0.80 v o l t$ and $E_{P t / F e^{3 +}, F e^{2 +}}^{\circ} = 0.77 v o l t$ .

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Solution

$E_{c e l l}^{\circ} = 0.03 v o l t, △ G^{\circ} = - n F E_{c e l l}^{\circ}$
$- 2895 J$ .

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Similar questions

Q. At equimolar concentrations of

F e^{2 +}

F e^{3 +}

[A g^{+}]

be so that the voltage of the galvanic cell made from

A g^{+} / A g

F e^{3 +} / F e^{2 +}

electrodes equals zero? The reaction is

F e^{2 +} + A g^{+} ⇌ F e^{3 +} + A g

. Determine the equilibrium constant at

25^{\circ} C

for the reaction. (Given:

E_{A g^{+} / A g}^{\circ} = 0.799 v o l t

E_{F e^{3 +} / F e^{2 +}}^{\circ} = 0.771 v o l t

Q. The two half-cell reactions of an electrochemical cell is given as

{A g}^{+} + e^{-} ⟶ A g; E_{{A g}^{+} | A g}^{o} = - 0.3995 V

{F e}^{2 +} ⟶ {F e}^{3 +} + e^{-}; E_{{F e}^{3 +} | {F e}^{2 +}}^{o} = - 0.7120 V

The value of cell EMF will be:

Q. At equimolar concentrations of

F e^{2 +}

F e^{3 +}

A g^{+}

] be so that the voltage of the galvanic cell made from the (

A g^{+} | A g)

F e^{3 +} | F e^{2 +})

electrodes equals zero ?

F e^{2 +} + A g^{+} ⇌ F e^{3 +} + A g

E_{A g^{o} | A g}^{o} = 0.7991; E_{F e^{3 +} | F e^{2 -}}^{o} = 0.771

Q. Answer, whether under standard conditions, the following reactions are possible or not:
(i) Will copper reduce

A g^{+}

A g

E_{A g^{+} / A g}^{\circ} = 0.799 v o l t; E_{C u^{2 +} / C u}^{\circ} = 0.337 v o l t

F e^{3 +}

F e^{2 +}

S n^{2 +}

F e^{3 +} / F e^{2 +} = 0.771 v o l t

;

S n^{2 +} / S n^{4 +} = - 0.250 v o l t

(iii) Would you use a silver spoon to stir a solution of

C u (N O_{3})_{2}

?

Q. At equimolar concentration of

F e^{2 +} and F e^{3 +}

[A g^{+}]

be so that the voltage of the galvanic cell made from

(A g^{+} / A g and F e^{3 +} / F e^{2 +})

electrodes equals zero? The reaction is

F e^{2 +} + A g^{+} ⇌ F e^{3 +} + A g

E_{A g^{+} / A g}^{0} = 0.799

E_{F e^{+} / F e^{2 +}}^{0} = 0.771 volt., 10^{- 0.47} = 2.94)

Give your answer upto two decimal only.

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