Question

Use elimination method for solving the following equations:
$3x+2y=0$, $x+3y=7$

Answer 1

Given equations are

$3x+2y=0$ ....(1)

and $x+3y=7$ ....(2)

Therefore, $3x=-2y\Rightarrow x=\frac{-2y}{3}$ ....(3)

On substituting this value in equation (2), we get

$\frac{-2y}{3}+3y=7$

$\Rightarrow -2y+9y=21$

$\Rightarrow 7y=21$

$\Rightarrow y=3$

Put this value in equation (3),

$x=\frac{-2\times 3}{3}$

$\Rightarrow x=-2$

Therefore, the solution is $x=-2,y=3$.