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Question

Use Euclid's algorithm to find the HCF of 408 and 1032.

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Solution

Given A =1032 b=408.
put value in a =bq=r(by euclids algorithm)
1032=408×2+216
408=216×1+192
216=192×1+24
192=24×8+0
Hence b=24
so HCF 408 and 1032 is 24.

1192820_1377430_ans_298313252499468581a959dd7b9d4391.JPG

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