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Question

Use factor theorem to verify that x+a is a factor of xn+an for nay odd positive integer.

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Solution

Let f(x)=xn+an.
In order to prove that x+a is a factor of f(x) for any odd positive integer n, it is sufficient to show that f(a)=0.
f(a)=(a)n+an=(1)nan+an
f(a)=(1+1)an [ n is odd positive integer ]
f(a)=0×an=0
Hence, x+a is a factor of xn+an, when n is an odd positive integer.

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