Use graph paper for the question.

The point P(2, -4) is reflected about the line = 0 to get the image Q. Point Q is reflected by the line y = 0 to get the image R.

Find area of figure PQR.

8 units²

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10 units²

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12 units²

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14 units²

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16 units²

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Solution

The correct option is E
16 units²

Q(-2 , -4), R(-2 , 4)

PQR is a right angled ∆.

PQ = 4 units & QR = 8 units

Area of ∆ PQR = ½ x PQ x QR

= 16 units²

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Use graph paper for the question. The point P(2, -4) is reflected about the line = 0 to get the image Q. Point Q is reflected by the line y = 0 to get the image R. Find area of figure PQR.

The correct option is E 16 units2Q(-2 , -4), R(-2 , 4) PQR is a right angled ∆. PQ = 4 units & QR = 8 units Area of ∆ PQR = ½ x PQ x QR = 16 units2

Use graph paper for the question.

The point P(2, -4) is reflected about the line = 0 to get the image Q. Point Q is reflected by the line y = 0 to get the image R.

Find area of figure PQR.

The correct option is E
16 units²

Q(-2 , -4), R(-2 , 4)

PQR is a right angled ∆.

PQ = 4 units & QR = 8 units

Area of ∆ PQR = ½ x PQ x QR

= 16 units²