Use identity to get the product of $(2 a - 7) (2 a - 7)$

4 a^{2} - 28 a - 49

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a^{2} + 14 a + 28

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a^{2} - 14 a - 28

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4 a^{2} - 28 a + 49

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Solution

The correct option is C $4 a^{2} - 28 a + 49$
$(2 a - 7) (2 a - 7)$
Using,
$(a - b)^{2} = a^{2} + b^{2} - 2 a b$
$= (2 a - 7)^{2}$
$= (2 a)^{2} + (7)^{2} - 2 (2 a) (7)$
$= 4 a^{2} + 49 - 28 a$

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