Question

Use identity to get the product of ${(\frac{2}{3}m+\frac{3}{2}n)}^2$

Answer 1

${(\frac{2}{3}m+\frac{3}{2}n)}^2$
Using,$(a+b{)}^2=a^2+b^2+2ab$
$={\left(\frac{2}{3}m\right)}^2+2\left(\frac{2}{3}m\right)\left(\frac{3}{2}n\right)+{\left(\frac{3}{2}n\right)}^2$
$=\frac{4}{9}{m}^2+2mn+\frac{9}{4}{n}^2$