Use property to evaluate (63)+(−53)+(−13)
90
We know that if a + b + c = 0, then a3+b3+c3 = 3abc
Here the components representing a,b, and c are 6,-5 and -1 respectively.
Hence a + b + c = 6 - 5 -1 = 0
Hence the first condition is satisfied.
So (63)+(−5)3+(−1)3 = 3(6 × (-5) ×(-1))
= 3 × 30
=90