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Question

Use property to evaluate: 73+33+(−10)3

A
210
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B
210
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C
630
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D
630
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Solution

The correct option is D 630
73+(3)3+(10)3
We know that
a3+b3+c33abc=(a+b+c)(a2+b2+c2abacbc)
If (a+b+c)=0, then.
a3+b3+c3=3abc
Here,
a=7
b=3
c=10
and a+b+c=7+310=0
Thus,
73+33+(10)3
=3(7)(3)(10)
=630

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