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B
−210
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C
630
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D
−630
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Solution
The correct option is D−630 73+(3)3+(−10)3 We know that a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−ac−bc) If (a+b+c)=0, then. a3+b3+c3=3abc Here, a=7 b=3 c=−10 and a+b+c=7+3−10=0 Thus, 73+33+(−10)3 =3(7)(3)(−10) =−630