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B
1960
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C
1560
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D
1735
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Solution
The correct option is C1560 133+(−8)3+(−5)3 We know that a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−ac−bc) If (a+b+c)=0, then. a3+b3+c3=3abc Here, a=13 b=−8 c=−5 and a+b+c=13−8−5=0 Thus, 133+(−8)3+(−5)3 =3(13)(−8)(−5) =1560