Use remainder theorem to find remainder when $p (x)$ is divided by $q (x)$ in the following questions:
$p (x) = 2 x^{2} - 5 x + 7, q (x) = x - 1$

Open in App

Solution

Given, $p (x) = 2 x^{2} - 5 x + 7$ and $q (x) = x - 1$

$q (x) \Rightarrow x - 1 = 0$ $\Rightarrow x = 1$

The remainder when $p (x)$ is divided by $q (x)$ is $p (1)$ (By Remainder Theorem)
Thus,
$p (1) = 2 (1)^{2} - 5 (1) + 7$
$p (1) = 2 - 5 + 7$
$p (1) = 4$

Suggest Corrections

Similar questions

p (x)

q (x)

A

p (x) = x^{9} - 5 x^{4} + 1, q (x) = x + 1

A + 10

P (x) =

12 x^{3} - 2 x^{2} + 18

Q (x) = 2 x - 12

P (x)

Q (x)

Using the remainder theorem, find the remainder, when p(x) is divided by g(x), where
$(p x) = x^{3} - 2 x^{2} - 8 x - 1, g (x) = x + 1$

p (x)

g (x)

p (x) = x^{3} + 3 x^{2} - 5 x + 8 g (x) = x - 3

x^{3} + p x^{2} + q x + r

x^{2} + p x + q

Join BYJU'S Learning Program