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Question

Use ruler and compass only for the following question. All construction lines and arcs must be clearly shown.
Construct a ABC in which BC=6.5 cm,ABC=60,AB=5 cm. Construct a locus of points l1 at a distance of 3.5 cm from A. Also, construct a locus of points l2 which is equidistant from AC and BC. Let l1 intersect l2 in two points X and Y. Measure XY.

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Solution

1. Draw base BC of length 6.5 cm. Make an angle of 60 from B.
2. Mark an arc of radius 5 cm from B on the 60 angle created and name it as A. Join AC. ABC is the required triangle.
3. Draw a circle with centre as A and radius 3.5 cm. This is the locus of the points equidistant from A at a distance of 3.5 cm.
4. Draw the angle bisector of ACB which will be the locus of points equidistant from AC and BC,
5. Measure the length of XY which comes out to be 5 cm.

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