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Question

Use suitable identities to find the following products:
(i) (x+4)(x+10)
(ii) (x+8)(x10)
(iii) (3x+4)(3x5)
(iv) (y2+32)(y232)
(v) (32x)(3+2x)

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Solution

We use identities
(x+a)(x+b)=x2+(a+b)x+ab and x2y2=(x+y)(xy)

(i) (x+4)(x+10)
=x2+(4+10)x+(4)(10)
=x2+14x+40

(ii) (x+8)(x10)
=x2+(810)+(8)(10)
=x22x80

(iii) (3x+4)(3x+5)
=(3x)2+(45)3x+(4)(5)
=9x23x20

(iv) (y2+32)(y232)
=(y2)2(32)2
=y494

(v) (32x)(3+2x)
=(3)2(2x)2=94x2

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