1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard IX
Mathematics
(x±a)(x±b) = x²±(a+b)x+ab.
Use suitable ...
Question
Use suitable identity
to solve
(
2
x
+
5
)
(
2
y
+
5
)
Open in App
Solution
Consider the given expression.
(
2
x
+
5
)
(
2
y
+
5
)
=
(
2
x
×
2
y
+
5
×
2
y
+
5
×
2
x
+
5
×
5
)
=
(
4
x
y
+
10
x
+
10
y
+
25
)
Hence, the value is
(
4
x
y
+
10
x
+
10
y
+
25
)
.
Suggest Corrections
0
Similar questions
Q.
Use a suitable identity to get following products.
(
2
y
+
5
)
(
2
y
+
5
)
Q.
Using a suitable identity, we can find out that
(
2
y
+
5
)
(
2
y
+
5
)
is equal to
Q.
Question 1(ii)
Use a suitable identity to get each of the following products:
(
2
y
+
5
)
(
2
y
+
5
)
Q.
Solve:
6
y
-
5
2
y
=
7
9
Q.
Solve using suitable property, state the property used.
8 x 5 x 125 x 20 x 6
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
(x+a)(x+b)
MATHEMATICS
Watch in App
Explore more
(x±a)(x±b) = x²±(a+b)x+ab.
Standard IX Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app