Use the BODMAS rule to reduce the expression: $x - 1 [(x^{2} + x - 2) (x^{2} - 1^{2}) \div (x - 1)^{2}]$ .

x^{3} + 2 x^{2} - x - 2

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x^{3} - 2 x^{2} - x - 2

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- x^{3} + 2 x^{2} - x - 2

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x^{3} + 2 x^{2} + x - +

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Solution

The correct option is A $x^{3} + 2 x^{2} - x - 2$
$x - 1 [(x^{2} + x - 2) (x^{2} - 1^{2}) \div (x - 1)^{2}]$
We need to follow BODMAS rule.
=> Brackets (parts of a calculation inside brackets always come first).
=> Orders (numbers involving powers or square roots).
=> Division.
=> Multiplication.
=> Addition.
=> Subtraction.
$=$ $\frac{x - 1 (x^{2} + x - 2) (x + 1) (x - 1)}{(x - 1 (x - 1)}$
$=$ $x^{3} + x^{2} - 2 x + x^{2} + x - 2$
$=$ $x^{3} + 2 x^{2} - x - 2$

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Similar questions

$(x + 1)$ is a factor of the polynomial
(a) $x^{3} - 2 x^{2} + x + 2$ (b) $x^{3} + 2 x^{2} + x - 2$
(c) $x^{3} + 2 x^{2} - x - 2$ (d) $x^{3} + 2 x^{2} - x + 2$

If dividend = $x^{4} + x^{3} - 2 x^{2} + x + 1$ , divisor = $x - 1$ and remainder = 2. Find the quotient q(x)

$If the dividend = x^{4} + x^{3} - 2 x^{2} + x + 1, divisor = x - 1 and remainder = 2, then find the quotient q(x) .$

Q. If dividend =

x^{4} + x^{3} - 2 x^{2} + x + 1

, divisor

= x - 1

and remainder

= 2

, then the quotient will be .

When $x^{4} + x^{3} - 2 x^{2} + x + 1$ is divided by x-1, the remainder is 2 and the quotient is q(x). Find q(x).

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Use the BODMAS rule to reduce the expression: x−1[(x2+x−2)(x2−12)÷(x−1)2].

Use the BODMAS rule to reduce the expression: $x - 1 [(x^{2} + x - 2) (x^{2} - 1^{2}) \div (x - 1)^{2}]$ .