Use the following information to answer the next question.
Arun has a combination of two plane mirrors, M1 and M2. The mirrors are placed at an angle θ with each other, as shown in the given figure.
A light ray is incident on M1, with the incident angle being 20°.
For what value of , will angle be 30°?
80°
The angle of incidence is always equal to the angle of reflection. Hence the given situation can be shown as:
∠PQX = ∠XQS = 20°
Since XQ is the normal to mirror M1, ∠SQR = 90° − 20° = 70°
It is given that ∠TSF = = 30°
Since YS is normal to mirror M2, ∠YST = 90° − 30° = 60°
∴ ∠QSY = ∠YST = 60°
Again, ∠QSR = 90° − ∠YSQ = 90° − 60° = 30°
In triangle ΔRQS:
θ + 70° + 30° = 180°
∴θ = 180° − 100° = 80°