Use the following information to answer the next question.
Two plane mirrors, M1 and M2 are placed at a right angle. A ray of light is incident on M1 at P1and gets reflected from M1. It then gets reflected from M2 at P2.
If OP1 = OP2, then the angle of reflection of the ray at P2 will be
45°
The angle of reflection is always equal to the angle of incidence. Let be the angle of incidence at P1 on mirror M1. The following figure shows the various angles the light ray makes with the mirrors, M1 and M2.
Since ∠M1OM2 is 90°, the normal XP1 on M1 is parallel to M2.
Therefore, ∠XP1P2 = ∠P1P2O =
Since P1O = OP2, ∠OP1P2 = ∠OP2P1 =
∴ 90° − =
2 = 90°
∴ = 45°
Since 90° − = 90° − 45° = 45°, all the angles will be 45°. Hence, all the reflected and the incident angles will be 45°