Use the formula to expand-3 3 n-43

We know that (x + y)3 = x3 + 3x2y + 3xy2 + y3. Comparing (3n + 4)3 with (x + y)3 , we get: x = 3n and y = 4 Substituting these in the above formula: (3n + 4)3 = ...

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Byju's Answer

Standard VIII

Physics

Static Friction

Use the formu...

Question

Use the formula to expand:

(3) (3n + 4)³

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Solution

We know that (x + y)³ = x³ + 3x²y + 3xy² + y³.
Comparing (3n + 4)³ with (x + y)³ , we get:
x = 3n and y = 4
Substituting these in the above formula:
(3n + 4)³= (3n)³ + 3 × (3n)² × 4 + 3 × 3n × 4² + 4³
= 27n³ + 108n² + 144n + 64

Suggest Corrections

Use the formula to expand: (3) (3n + 4)3

We know that (x + y)3 = x3 + 3x2y + 3xy2 + y3. Comparing (3n + 4)3 with (x + y)3 , we get: x = 3n and y = 4 Substituting these in the above formula: (3n + 4)3 = (3n)3 + 3 × (3n)2 × 4 + 3 × 3n × 42 + 43 = 27n3 + 108n2 + 144n + 64

Use the formula to expand:

(3) (3n + 4)³

We know that (x + y)³ = x³ + 3x²y + 3xy² + y³.
Comparing (3n + 4)³ with (x + y)³ , we get:
x = 3n and y = 4
Substituting these in the above formula:
(3n + 4)³= (3n)³ + 3 × (3n)² × 4 + 3 × 3n × 4² + 4³
= 27n³ + 108n² + 144n + 64