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Question
Use the formula to find the factors.
(6) 121 – 49n2
(6) 121 – 49n2
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Solution
121 – 49n2
= (11)2 – (7n)2
= (11 + 7n) (11 – 7n) [a2 – b2 = (a + b) (a – b)]
∴ 121 – 49n2 = (11 + 7n) (11 – 7n)
= (11)2 – (7n)2
= (11 + 7n) (11 – 7n) [a2 – b2 = (a + b) (a – b)]
∴ 121 – 49n2 = (11 + 7n) (11 – 7n)
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