wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Use the formulato explain why the speed of sound in air

(a) is independent of pressure,

(b) increases with temperature,

(c) increases with humidity.

Open in App
Solution

(a) Take the relation:

Now from the ideal gas equation for n = 1:

PV = RT

For constant T, PV = Constant

Since both M and γ are constants, v = Constant

Hence, at a constant temperature, the speed of sound in a gaseous medium is independent of the change in the pressure of the gas.

(b) Take the relation:

For one mole of an ideal gas, the gas equation can be written as:

PV = RT

P = … (ii)

Substituting equation (ii) in equation (i), we get:

Where,

Mass, M = ρV is a constant

γ and R are also constants

We conclude from equation (iv) that .

Hence, the speed of sound in a gas is directly proportional to the square root of the temperature of the gaseous medium, i.e., the speed of the sound increases with an increase in the temperature of the gaseous medium and vice versa.

(c) Letbe the speeds of sound in moist air and dry air respectively.

Letbe the densities of moist air and dry air respectively.

Take the relation:

Hence, the speed of sound in moist air is:

And the speed of sound in dry air is:

On dividing equations (i) and (ii), we get:

However, the presence of water vapour reduces the density of air, i.e.,

Hence, the speed of sound in moist air is greater than it is in dry air. Thus, in a gaseous medium, the speed of sound increases with humidity.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Speed of Sound
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon