Use the given standard enthalpies of formation to determine the heat of reaction of the following reactions:
TiCl4(g)+2H2O(g)→TiO2(g)+4HCl(G)
△H∘fTiCl4(g)=−736.2 kJ/mole △H∘fTiO2(g)=−944.7 kJ/mole
△H∘fH2O(g)=−241.8 kJ/mole △H∘fHCl(g)=−92.3 kJ/mole.
A −278.1−278.1 | |
B +369.2+369.2 | |
C +67.1+67.1 | |
D −67.1 |