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Question

Use the identity (a+b)(ab)=a2b2 to evaluate:
103×97.

A
8881
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B
9991
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C
9981
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D
9891
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Solution

The correct option is B 9991

We know, 103×97=(100+3)×(1003) .
Applying the formula (a+b)(ab)=a2b2, where a=100,b=3,

we get,
103×97=(100+3)×(1003)=100232=100009=9991.

Therefore, option B is correct.


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