1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard VIII
Mathematics
Algebraic Identities
Use the ident...
Question
Use the identity
(
a
+
b
)
(
a
−
b
)
=
a
2
−
b
2
to evaluate:
33
×
27
.
A
891
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
881
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
981
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
841
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
A
891
We know,
33
×
27
=
(
30
+
3
)
×
(
30
−
3
)
.
Applying the formula
(
a
+
b
)
(
a
−
b
)
=
a
2
−
b
2
,
where
a
=
30
,
b
=
3
,
we get,
33
×
27
=
(
30
+
3
)
×
(
30
−
3
)
=
30
2
−
3
2
=
900
−
9
=
891
.
Therefore, option
A
is correct.
Suggest Corrections
0
Similar questions
Q.
Use the identity
(
a
+
b
)
(
a
−
b
)
=
a
2
−
b
2
to evaluate:
9.8
×
10.2
.
Q.
Evaluate
[
{
337
}
2
−
{
336
}
2
]
[ use identity
(
a
2
−
b
2
)
=
(
a
+
b
)
(
a
−
b
)
Q.
Using the identity
(
a
2
−
b
2
)
=
(
a
+
b
)
(
a
−
b
)
, evaluate
(
0.8
)
2
−
(
0.2
)
2
Q.
Evaluate by using identity
(
a
+
b
)
(
a
−
b
)
=
a
2
−
b
2
(
5
a
+
3
b
)
(
5
a
−
3
b
)
Q.
Evaluate the following using the identity
(
a
+
b
)
(
a
−
b
)
=
a
2
−
b
2
(
x
+
3
)
(
x
−
3
)
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Algebraic Identities
MATHEMATICS
Watch in App
Explore more
Algebraic Identities
Standard VIII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app