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Question

Use the identity (a+b)(ab)=a2b2 to evaluate:
33×27.

A
891
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B
881
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C
981
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D
841
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Solution

The correct option is A 891
We know, 33×27=(30+3)×(303) .
Applying the formula (a+b)(ab)=a2b2, where a=30,b=3,
we get,
33×27=(30+3)×(303)=30232=9009=891 .
Therefore, option A is correct.

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