Use the identity (x - a)(x - b) to find the product of
(4x - 5)(4x -1).
$[2 M a r k s]$

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Solution

(x - a)(x - b)=x² - (a + b)x + ab

(4x - 5)(4x -1)
a=5, b= 1,x=4x
$[1 M a r k]$

(4x - 5)(4x - 1)= (4x)² - [5 + 1](4x) + (-5) (-1)

(4x - 5)(4x - 1)= 16x² - 24x + 5
$[1 M a r k]$

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Question 2(iv)
Use the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$ to find the following products:
$(4 x + 5) (4 x - 1)$

(x + a) (x + b) = x^{2} + (a + b) x + a b

(x + 3) (x + 7)

(4 x + 5) (4 x + 1)

(4 x - 5) (4 x - 1)

(4 x + 5) (4 x - 1)

(2 x + 5 y) (2 x + 3 y)

(2 a^{2} + 9) (2 a^{2} + 5)

(x y z - 4) (x y z - 2)

[2 M a r k s]

(x + a) (x + b) = x^{2} + (a + b) x + a b

(4 x - 5) (4 x - 1)

(x + a) (x + b) = x^{2} + (a + b) x + a b

(4 x + 5) (4 x - 1)

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