Use the identity (x -a)(x - b) to find the product of
(xyz - 4)(xyz - 2).
$[2 M a r k s]$

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Solution

(x - a)(x - b)=x² + (a-b)x + ab

(xyz - 4)(xyz - 2)
a=4, b= 2, x=xyz
$[1 M a r k]$

(xyz - 4)(xyz - 2) = (xyz)² - (4 + 2)(xyz) + (4)(2)

(xyz - 4)(xyz - 2)= (xyz)² - 6xyz + 8
$[1 M a r k]$

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Similar questions

(x + a) (x + b) = x^{2} + (a + b) x + a b

(x y z - 4) (x y z - 2)

Use the identity (x + a) (x + b) = x² + (a + b)x + ab to find the following products.

(i) (x + 3) (x + 7) (ii) (4x +5) (4x + 1)

(iii) (4x − 5) (4x − 1) (iv) (4x + 5) (4x − 1)

(v) (2x +5y) (2x + 3y) (vi) (2a² +9) (2a² + 5)

(vii) (xyz − 4) (xyz − 2)

(x + a) (x + b) = x^{2} + (a + b) x + a b

(x y z + 4) (x y z + 2)

[2 M a r k s]

[2 M a r k s]

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