Use the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$ to find the given product:
$(4 x + 5)$ $(4 x - 1)$ .

16 x^{2} + 16 x - 5

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16 x^{2} - 16 x - 5

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16 x^{2} + 16 x + 5

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16 x^{2} + 12 x - 5

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Solution

The correct option is A $16 x^{2} + 16 x - 5$
Given, $(4 x + 5) (4 x - 1)$ .

We know, $(x + a) (x + b) = x^{2} + (a + b) x + a b$ .

On comparing, we get,
$x = 4 x, a = 5, b = - 1$ .

Thus,
$= (4 x + 5) (4 x - 1)$
$= (4 x)^{2} + [(5) + (- 1)] 4 x + (5) \times (- 1)$
$= 16 x^{2} + (4) 4 x + (- 5)$
$= 16 x^{2} + 16 x - 5$ .

Hence, option $A$ is correct.

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