Use the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$ to find the following product.
$(4 x + 5) (4 x + 1)$

x^{2} + 24 x + 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 x^{2} + 24 x + 5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

16 x^{2} + 24 x + 6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 x^{2} - 24 x + 6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $16 x^{2} + 24 x + 5$
Given: $(4 x + 5) (4 x + 1)$

Using, $(x + a) (x + b) = x^{2} + (a + b) x + a b$ we get,

$= 16 x^{2} + (5 + 1) 4 x + 5$

$= 16 x^{2} + 24 x + 5$

Suggest Corrections

Similar questions

16 x^{2} - 24 x + 9 = 0

16 x^{2} - 24 x = 0

(x + a) (x + b) = x^{2} + (a + b) x + a b

(4 x - 5) (4 x - 1)

The value of the expression $16 x^{2} + 24 x + 9$ for $x = 0$ is _____.

Join BYJU'S Learning Program