Use the identity (x+a)(x+b)=x2+(a+b)x+ab
to find (4x−5)(4x−1).
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Solution
The given identity is: (x+a)(x+b)=x2+(a+b)x+ab
So, using the same identity, the expansion of the given expression is given as: (4x−5)(4x−1)=(4x)2+(−5−1)x+(−5)(−1) =16x2−6x+5