Question 2(vii)
Use the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$ to find the following products:
$(x y z - 4) (x y z - 2)$

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Solution

$(x y z - 4) (x y z - 2)$
$= (x y z)^{2} + (- 4 - 2) \times x y z + (- 4) \times (- 2)$ $[U s i n g i d e n t i t y (x + a) (x + b) = x^{2} + (a + b) x + a b]$
$= x^{2} y^{2} z^{2} - 6 x y z + 8$

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Similar questions

(x + a) (x + b) = x^{2} + (a + b) x + a b

(x + a) (x + b) = x^{2} + (a + b) x + a b

(x y z + 4) (x y z + 2)

(x + a) (x + b) = x^{2} + (a + b) x + a b

(x + 3) (x + 7)

Question 2(i)
Use the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$ to find the following products:
(x+3)(x+7)

Use the identity (x + a) (x + b) = x² + (a + b)x + ab to find the following products.

(i) (x + 3) (x + 7) (ii) (4x +5) (4x + 1)

(iii) (4x − 5) (4x − 1) (iv) (4x + 5) (4x − 1)

(v) (2x +5y) (2x + 3y) (vi) (2a² +9) (2a² + 5)

(vii) (xyz − 4) (xyz − 2)

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