Use the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$ to find the following product.
$(4 x - 5) (4 x - 1)$

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Solution

Using the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$
$(4 x - 5) \times (4 x - 1) = {(4 x)}^{2} + (- 5 - 1) \times (4 x) + (- 5) \times (- 1) = 16 x^{2} + (- 6) \times (4 x) + 5 = 16 x^{2} - 24 x + 5$
Hence, $(4 x - 5) (4 x - 1) = 16 x^{2} - 24 x + 5$ .

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Question 2(iii)
Use the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$ to find the following products:
$(4 x - 5) (4 x - 1)$

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