Use the information given in the adjoining figure to find:
(i)The length of AC.
(ii)The are a of ΔABC.
(iii)The length of BD, correct to one decimal place.
AB=24 cm, BC=7 cm
(i)AC=√AB2+BC2
=√242+72
=√576+49
=√625=24cm
(ii)Area of ΔABC=12AB×BC
=12×24×7=84cm2
(iii)BD⊥AC
Area ΔABC=12AC×BD
84=12×25×BD
⇒BD=84×225=16825=6.72cm
=6.7 cm