Use the numbers $0, \frac{1}{4}, \frac{1}{2}, \frac{2}{3}$ or $1$ to show what you think the probability is if I throw a die, the score will be at least $3$ .

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Solution

Determining the probability:
When a die is thrown the possible outcomes are:
$1, 2, 3, 4, 5, 6$
The outcomes having a score of at least $3$ are:
$3, 4, 5, 6$
So, we have the total number of outcomes $= 52$
and number of favorable outcomes $= 13$
The formula for probability is
$P r o b a b i l i t y = \frac{N u m b e r o f f a v o r a b l e o u t c o m e s}{T o t a l n u m b e r o f o u t c o m e s} \Rightarrow P (a t l e a s t 3) = \frac{4}{6} ∴ P (a t l e a s t 3) = \frac{2}{3}$
Therefore, the probability of the score will at least $3$ is $\frac{2}{3}$ .

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