Question

Use the rules to determine which number is bigger and which is smaller.

(6) $\frac{19}{15},\frac{4}{3}$

Answer 1

$$\begin{gathered} \frac{19}{15},\frac{4}{3} \\ \mathrm{Let}\frac{19}{15}=\frac{a}{b}\mathrm{and}\frac{4}{3}=\frac{c}{d} \end{gathered}$$
Then, a × d = 19 × 3 = 57
And b × c = 15 × 4 = 60
57 < 60
∴ a × d < b × c
$$\begin{gathered} \therefore \frac{a}{b}<\frac{c}{d} \\ \therefore \frac{19}{15}<\frac{4}{3} \end{gathered}$$