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Solving a Quadratic Equation by Completion of Squares Method

Use the Zero ...

Question

Use the Zero Product Property to solve the equation $(7 x + 2) (5 x - 4) = 0$

\frac{2}{7}

\frac{- 4}{5}

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\frac{- 2}{7}

\frac{4}{5}

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\frac{- 2}{5}

\frac{7}{5}

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\frac{2}{5}

\frac{- 7}{5}

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Solution

The correct option is A $\frac{- 2}{7}$ , $\frac{4}{5}$
$(7 x + 2) (5 x - 4) = 0 (7 x + 2) = 0; (5 x - 4) = 0 x = - \frac{2}{7}; x = \frac{4}{5}$

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Similar questions

\frac{2}{3} \times \frac{4}{5} = \frac{4}{5} \times \frac{2}{3}

(\frac{- 3}{4}) \times 1 = \frac{- 3}{4} = 1 \times (\frac{- 3}{4})

(\frac{- 17}{28}) \times (\frac{- 28}{17}) = 1

\frac{1}{5} \times (\frac{7}{8} \times \frac{4}{3}) = (\frac{1}{5} \times \frac{7}{8}) \times \frac{4}{3}

\frac{2}{7} \times (\frac{9}{10} + \frac{2}{5}) = \frac{2}{7} \times \frac{9}{10} + \frac{2}{7} \times \frac{2}{5}

\frac{4}{5} + \frac{11}{7} + \frac{- 7}{5} + \frac{- 2}{7}

\frac{2}{3} \times [\frac{3}{4} \times \frac{5}{7}]

[\frac{2}{3} \times \frac{5}{7}] \times \frac{3}{4}

\frac{2}{3} \times [\frac{3}{4} \times \frac{5}{7}]

[\frac{2}{3} \times \frac{5}{7}] \times \frac{3}{4}

5 p^{2} - 7 p - 3 = 0

5 q^{2} - 7 q - 3 = 0

p \neq q

5 p - 4 q

5 q - 4 p

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