Use Venn diagrams to verify De'Morgan's law of complementation $(A \cup B)^{'} = A^{'} \cup B^{'}$

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Solution

From $(1)$ and $(2)$
$(A \cup B)^{'} = A^{'} \cap B^{'}$

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Similar questions

Use Venn diagrams to verify De Morgan’s law of complementation (A $\cup$ B)’ = A’ $\cap$ B’

A ∖ (B \cap C) = (A ∖ B) \cup (A ∖ C)

A ∖ (B \cap C) = (A ∖ B) \cup (A ∖ C)

(A \cap B)^{'} = A^{'} \cup B^{'}

U = {- 2, - 1, 0, 1, 2, 3, . . . ., 10}, A = {- 2, 2, 3, 4, 5}

B = {1, 3, 5, 8, 9}

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