The correct option is B 4 to 6
Ka=10−5
pKa=−log10Ka=−log1010−5=5
pH=pKa+log[Conjugate Base][Acid]
When, [Conjugate Base][Acid]=110
pH=5+log110
pH=5+log0.1
pH=5−1
pH=4
When, [Conjugate Base][Acid]=101
pH=5+log101
pH=5+log10
pH=5+1
pH=6
Useful buffer range of weak acid HA is 4 to 6.