Question

Usha swims $90\mathrm{m}$long pool. She covers $180\mathrm{m}\mathrm{in}1\min$ by swimming from one end to the other and back along the same straight path to find the average speed of Usha?

Answer 1

Step1:Given:

Distance covered by Usha, S=$180m$

Time [t] taken by Usha to cover the distance = $1min=60s$

Step2: Formula used:

$Averagespeed{v}_{av}=dis\tan ce\left[S\right]/time\left[t\right]$

Step3: Final solution:

$$\begin{gathered} v_{av}=S/t \\ {v}_{av}=180/60 \\ {v}_{av}=3m/s \end{gathered}$$

Thus, the average speed of Usha to cover the distance of $180\mathrm{m}\mathrm{is}3\mathrm{m}/\mathrm{s}$.