Using $14^{2} = 196$ can you calculate these powers?
(i) $(1.4)^{2}$
(ii) $(0.14)^{2}$
(iii) $(0.014)^{2}$

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Solution

Given: $14^{2} = 196$
(i) $(1.4)^{2}$
$(1.4)^{2}$
$= (\frac{14}{10})^{2}$
$= \frac{196}{100}$
$= 1.96$
Therefore, $(1.4)^{2} = 1.96$

(ii) $(0.14)^{2}$
$(0.14)^{2}$
$= (\frac{14}{100})^{2}$
$= \frac{196}{10000}$
$= 0.0196$
Therefore, $(0.14)^{2} == 0.0196$

(iii) $(0.014)^{2}$
$(0.014)^{2}$
$= (\frac{14}{1000})^{2}$
$= \frac{196}{1000000}$
$= 0.000196$
Therefore, $(0.014)^{2} == 0.000196$

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