Question

Using 3,4,5,6,7,8(repetition allowed) how many numbers between 3000 and 4000 can be formed which are divisible by 5?

• A. 18
• B. 20
• C. 36
• D. 12

Answer 1

The correct option is C 36

From the given no.s 3,4,5,6,7,8, to form numbers that are divisible by 5, last digit must be 5
and for the number to lie between 3000-4000, the first digit should be 3

number of places left = 2
$\frac{3}{\left(\mathrm{fix}\right)}\frac{\left(2\mathrm{nd}\right)}{}\frac{\left(3\mathrm{rd}\right)}{}\frac{5}{\left(\mathrm{fix}\right)}$ both, 2nd and 3rd places can be filled with 6 numbers to form distinct no.s lying between 3000 and 4000 and which are divisible by 5.
so total numbers$=(6\times 6)\to 36\mathrm{option}\left(c\right)\mathrm{is}\mathrm{correct}$