Question

Using $4$ different elements, the number of different matrices can be formed, is

• A. $12$
• B. $36$
• C. $72$
• D. $96$

Answer 1

The correct option is C $72$

Given : total elements in matrix $=4.$
Possible orders are $1\times 4,4\times 1,2\times 2$
and each ordered matrix have total $4!$ (all elements are different) ways to arrange.
So, total possible matrices $=3\times 4!=72$