Using $a^{2} - b^{2} = (a + b) (a - b)$ , find
$51^{2} - 49^{2}$

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Solution

Using the identity
$a^{2} - b^{2} = (a + b) (a - b)$
$51^{2} - 49^{2}$
Put
$a = 51, b = 49$
So,
$51^{2} - 49^{2} = (51 + 49) (51 - 49) 51^{2} - 49^{2} = 100 \times 2 51^{2} - 49^{2} = 200$
Hence, $51^{2} - 49^{2} = 200$ .

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Similar questions

Using a²− b² = (a + b) (a − b), find

(i) 51² − 49² (ii) (1.02)² − (0.98)² (iii) 153² − 147²

(iv) 12.1² − 7.9²

a^{2} - b^{2} = (a + b) (a - b)

51^{2} - 49^{2}

Using $a^{2} - b^{2} = (a + b) (a - b),$ find
$51^{2} - 49^{2}$ .

Using a²−b² = (a + b) (a − b),find

(i) 51² −49² (ii) (1.02)² − (0.98)² (iii) 153² − 147²

(iv) 12.1² −7.9²

Using a²− b² = (a + b) (a − b), find

(i) 51² − 49² (ii) (1.02)² − (0.98)² (iii) 153² − 147²

(iv) 12.1² − 7.9²

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