Using $a^{2} - b^{2} = (a + b) (a - b)$ , find
${1.02}^{2} - {0.98}^{2}$

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Solution

$(1.02)^{2} - (0.98)^{2}$
$= (1.02 + 0.98) (1.02 - 0.98)$ [ $∵ a^{2} - b^{2} = (a + b) (a - b)$ ]
$= (2) (0.04)$
$= 0.08$
$(1.02)^{2} - (0.98)^{2} = 0.08$ .

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Similar questions

Using a²-b²=(a+b)(a-b) find:

i. 51² - 49²

ii. (1.02)² - (0.98)²

Using a²− b² = (a + b) (a − b), find

(i) 51² − 49² (ii) (1.02)² − (0.98)² (iii) 153² − 147²

(iv) 12.1² − 7.9²

Using the identity a^{2} - b^{2} = (a + b) (a - b)

Find the value of (1.02)^{2} - (0.98)^{2} .

a^{2} - b^{2} = (a + b) (a - b),

(1.02)^{2} - (0.98)^{2}

a^{2} - b^{2} = (a + b) (a - b),

(1.02)^{2} - (0.98)^{2}

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