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Question

Using a suitable identity, find each of the following products:
(2l3m)(2l+3m)

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Solution

We need to multiply the polynomials (2l3m)(2l+3m)
By using identity (a+b)(ab)=a2b2, we can find the product.
Here a=2l,b=3m
Therefore, (2l3m)(2l+3m)=4l29m2
This is the required answer.

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